Antipode of Panbang, Bhutan
The opposite side of the world to Panbang is Coquimbo, Coquimbo Region, Chile.
Panbang
Bhutan
Continent: Asia
Coordinates: 26.867, 90.983
Antipodal point
South Pacific Ocean
Exact location on the other side of the world
Coordinates: -26.867, -89.017
Coquimbo
Chile
Coquimbo is the closest city to Panbang's antipodal point (1,764 km).
The antipodal city to Panbang is Coquimbo. This means that, among all the populated locations in the world, the farthest city from Panbang is Coquimbo.
The distance from Panbang to Coquimbo is about 18,000 kilometers. A direct flight would take around 20 hours, but there aren't commercial routes between these cities.
Cities on the other side of the world of Panbang
This table contains the populated locations that are closest to Panbang's antipode. These are the farthest cities in the world from Panbang.
| City | Country | Distance from antipode | Coordinates |
|---|---|---|---|
| Coquimbo, Coquimbo Region | Chile | 1,764 km | (-29.953, -71.339) |
| La Serena, Coquimbo Region | Chile | 1,772 km | (-29.906, -71.250) |
| Ovalle, Coquimbo Region | Chile | 1,787 km | (-30.601, -71.199) |
| Vallenar, Atacama | Chile | 1,809 km | (-28.576, -70.759) |
| Valparaíso | Chile | 1,809 km | (-33.036, -71.630) |
| Illapel, Coquimbo Region | Chile | 1,811 km | (-31.633, -71.170) |
| Monte Patria, Coquimbo Region | Chile | 1,811 km | (-30.695, -70.958) |
| Viña del Mar, Valparaíso | Chile | 1,816 km | (-33.025, -71.552) |
| Vicuña, Coquimbo Region | Chile | 1,825 km | (-30.035, -70.713) |
| Quilpué, Valparaíso | Chile | 1,826 km | (-33.048, -71.442) |
Local time:
Time Zone: Asia/Thimphu
Coordinates: 26.8667° N 90.9833° E
Elevation: 214 m (702 ft)
Local time:
Time Zone: America/Santiago
Coordinates: 29.9533° S 71.3395° W
Elevation: 22 m (72 ft)
How to calculate the antipodal point?
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
- LatO: Latitude at the origin point.
- LngO: Longitude at the origin point.
- LatA: Latitude at the antipodal point.
- LngA: Longitude at the antipodal point.
Step 1: Obtain the geographic coordinates of Panbang
The DMS coordinates are: 26°52'0'' N 90°58'60'' E .
Calculations are easier by using the decimal format, hence:
LatO = 26.86667°
LngO = 90.98333°
Step 2: Calculate the latitude
LatA = - LatO = -26.86667°
Since the latitude is positive (north direction), the antipode must be negative (south direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = 90.98333 - 180° = -89.01667°
Since the longitude is positive, we subtract 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would sum 180° for the same reason.
Result:
The antipode of Panbang is located on coordinates: (LatA, LngA) = (-26.86667, -89.01667)
In DMS format: 26°52'0'' N 90°58'60'' E .