The opposite side of the world to Sherbrooke is Augusta, Western Australia, Australia.
Canada
Continent: America
Coordinates: 45.400, -71.899
Indian Ocean
Exact location on the other side of the world
Coordinates: -45.400, 108.101
Australia
Augusta is the closest city to Sherbrooke's antipodal point (1,370 km).
The antipodal city to Sherbrooke is Augusta. This means that, among all the populated locations in the world, the farthest city from Sherbrooke is Augusta.
The distance from Sherbrooke to Augusta is about 19,000 kilometers. A direct flight would take around 21 hours, but there aren't commercial routes between these cities.
This table contains the populated locations that are closest to Sherbrooke's antipode. These are the farthest cities in the world from Sherbrooke.
City | Country | Distance from antipode | Coordinates |
---|---|---|---|
Augusta, WA | Australia | 1,370 km | (-34.316, 115.159) |
Ocean Beach, WA | Australia | 1,391 km | (-35.014, 117.290) |
Pemberton, WA | Australia | 1,391 km | (-34.443, 116.037) |
Shadforth, WA | Australia | 1,395 km | (-34.964, 117.269) |
Gnarabup, WA | Australia | 1,396 km | (-33.993, 114.996) |
Denmark, WA | Australia | 1,400 km | (-34.961, 117.353) |
Youngs, WA | Australia | 1,402 km | (-35.017, 117.517) |
Margaret River, WA | Australia | 1,403 km | (-33.955, 115.076) |
Grasmere, WA | Australia | 1,414 km | (-35.018, 117.756) |
Little Grove, WA | Australia | 1,415 km | (-35.068, 117.872) |
Local time:
Time Zone: America/Toronto
Coordinates: 45.4001° N 71.8991° W
Elevation: 175 m (574 ft)
Local time:
Time Zone: Australia/Perth
Coordinates: 34.3157° S 115.1592° E
Elevation: 37 m (121 ft)
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
Step 1: Obtain the geographic coordinates of Sherbrooke
The DMS coordinates are: 45°24'0.3'' N 71°53'56.7'' W.
Calculations are easier by using the decimal format, hence:
LatO = 45.40008°
LngO = -71.89908°
Step 2: Calculate the latitude
LatA = - LatO = -45.40008°
Since the latitude is positive (north direction), the antipode must be negative (south direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = -71.89908 + 180° = 108.10092°
Since the longitude is negative, we sum 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would subtract 180° for the same reason.
Result:
The antipode of Sherbrooke is located on coordinates: (LatA, LngA) = (-45.40008, 108.10092)
In DMS format: 45°24'0.3'' N 71°53'56.7'' W.