The opposite side of the world to Acapulco de Juárez is Port Mathurin, Rodrigues, Mauritius.
Mexico
Continent: America
Coordinates: 16.849, -99.909
Indian Ocean
Exact location on the other side of the world
Coordinates: -16.849, 80.091
Mauritius
Port Mathurin is the closest city to Acapulco de Juárez's antipodal point (1,790 km).
The antipodal city to Acapulco de Juárez is Port Mathurin. This means that, among all the populated locations in the world, the farthest city from Acapulco de Juárez is Port Mathurin.
The distance from Acapulco de Juárez to Port Mathurin is about 18,000 kilometers. A direct flight would take around 20 hours, but there aren't commercial routes between these cities.
This table contains the populated locations that are closest to Acapulco de Juárez's antipode. These are the farthest cities in the world from Acapulco de Juárez.
City | Country | Distance from antipode | Coordinates |
---|---|---|---|
Port Mathurin, Rodrigues | Mauritius | 1,790 km | (-19.683, 63.417) |
Baie aux Huîtres, Rodrigues | Mauritius | 1,791 km | (-19.694, 63.408) |
West Island | Cocos Islands | 1,876 km | (-12.157, 96.823) |
Meedhoo, Seenu | Maldives | 1,950 km | (-0.583, 73.233) |
Hithadhoo, Seenu | Maldives | 1,955 km | (-0.600, 73.083) |
Fuvahmulah, Gnyaviyani Atoll | Maldives | 1,971 km | (-0.299, 73.424) |
Gadhdhoo, Gaafu Dhaalu Atoll | Maldives | 2,031 km | (0.290, 73.457) |
Vaadhoo, Gaafu Dhaalu Atoll | Maldives | 2,031 km | (0.227, 73.273) |
Thinadhoo, Gaafu Dhaalu Atoll | Maldives | 2,074 km | (0.531, 73.000) |
Viligili, Gaafu Alif Atoll | Maldives | 2,080 km | (0.759, 73.433) |
Local time:
Time Zone: America/Mexico_City
Coordinates: 16.8494° N 99.9089° W
Elevation: 16 m (52 ft)
Local time:
Time Zone: Indian/Mauritius
Coordinates: 19.6833° S 63.4167° E
Elevation: 44 m (144 ft)
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
Step 1: Obtain the geographic coordinates of Acapulco de Juárez
The DMS coordinates are: 16°50'57.9'' N 99°54'32.1'' W.
Calculations are easier by using the decimal format, hence:
LatO = 16.84942°
LngO = -99.90891°
Step 2: Calculate the latitude
LatA = - LatO = -16.84942°
Since the latitude is positive (north direction), the antipode must be negative (south direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = -99.90891 + 180° = 80.09109°
Since the longitude is negative, we sum 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would subtract 180° for the same reason.
Result:
The antipode of Acapulco de Juárez is located on coordinates: (LatA, LngA) = (-16.84942, 80.09109)
In DMS format: 16°50'57.9'' N 99°54'32.1'' W.