The opposite side of the world to Cagayan de Oro is Novo Progresso, Pará, Brazil.
Philippines
Continent: Asia
Coordinates: 8.482, 124.647
Brazil
Continent: South America
Coordinates: -8.482, -55.353
Brazil
Novo Progresso is the closest city to Cagayan de Oro's antipodal point (160 km).
The antipodal city to Cagayan de Oro is Novo Progresso. This means that, among all the populated locations in the world, the farthest city from Cagayan de Oro is Novo Progresso.
The distance from Cagayan de Oro to Novo Progresso is about 20,000 kilometers. A direct flight would take around 22 hours, but there aren't commercial routes between these cities.
This table contains the populated locations that are closest to Cagayan de Oro's antipode. These are the farthest cities in the world from Cagayan de Oro.
City | Country | Distance from antipode | Coordinates |
---|---|---|---|
Novo Progresso, PA | Brazil | 160 km | (-7.041, -55.420) |
Novo Mundo, MT | Brazil | 166 km | (-9.976, -55.178) |
Guarantã do Norte, MT | Brazil | 170 km | (-9.951, -54.908) |
Alta Floresta, MT | Brazil | 174 km | (-9.876, -56.086) |
Terra Nova do Norte, MT | Brazil | 235 km | (-10.597, -55.117) |
Apiacás, MT | Brazil | 254 km | (-9.562, -57.390) |
Itaúba, MT | Brazil | 280 km | (-11.008, -55.242) |
Nova Monte Verde, MT | Brazil | 285 km | (-9.980, -57.467) |
Marcelândia, MT | Brazil | 302 km | (-11.082, -54.518) |
Tabaporã, MT | Brazil | 351 km | (-11.308, -56.819) |
Local time:
Time Zone: Asia/Manila
Coordinates: 8.4822° N 124.6472° E
Elevation: 8 m (26 ft)
Local time:
Time Zone: America/Santarem
Coordinates: 7.0412° S 55.4196° W
Elevation: 193 m (633 ft)
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
Step 1: Obtain the geographic coordinates of Cagayan de Oro
The DMS coordinates are: 8°28'56'' N 124°38'50'' E .
Calculations are easier by using the decimal format, hence:
LatO = 8.48222°
LngO = 124.64722°
Step 2: Calculate the latitude
LatA = - LatO = -8.48222°
Since the latitude is positive (north direction), the antipode must be negative (south direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = 124.64722 - 180° = -55.35278°
Since the longitude is positive, we subtract 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would sum 180° for the same reason.
Result:
The antipode of Cagayan de Oro is located on coordinates: (LatA, LngA) = (-8.48222, -55.35278)
In DMS format: 8°28'56'' N 124°38'50'' E .