The opposite side of the world to Oxford is Portobello, Otago, New Zealand.
United Kingdom
Continent: Europe
Coordinates: 51.752, -1.256
South Pacific Ocean
Exact location on the other side of the world
Coordinates: -51.752, 178.744
New Zealand
Portobello is the closest city to Oxford's antipodal point (885 km).
The antipodal city to Oxford is Portobello. This means that, among all the populated locations in the world, the farthest city from Oxford is Portobello.
The distance from Oxford to Portobello is about 19,000 kilometers. A direct flight would take around 21 hours, but there aren't commercial routes between these cities.
This table contains the populated locations that are closest to Oxford's antipode. These are the farthest cities in the world from Oxford.
City | Country | Distance from antipode | Coordinates |
---|---|---|---|
Portobello, Otago | New Zealand | 885 km | (-45.850, 170.650) |
Macandrew Bay, Otago | New Zealand | 886 km | (-45.867, 170.600) |
Tainui, Otago | New Zealand | 886 km | (-45.901, 170.523) |
Andersons Bay, Otago | New Zealand | 886 km | (-45.896, 170.531) |
Saint Clair, Otago | New Zealand | 887 km | (-45.917, 170.483) |
Shiel Hill, Otago | New Zealand | 887 km | (-45.888, 170.530) |
Musselburgh, Otago | New Zealand | 887 km | (-45.897, 170.515) |
Waverley, Otago | New Zealand | 887 km | (-45.882, 170.539) |
Saint Kilda, Otago | New Zealand | 887 km | (-45.902, 170.502) |
Papatowai, Otago | New Zealand | 888 km | (-46.561, 169.471) |
Local time:
Time Zone: Europe/London
Coordinates: 51.7522° N 1.256° W
Elevation: 72 m (236 ft)
Local time:
Time Zone: Pacific/Auckland
Coordinates: 45.85° S 170.65° E
Elevation: 77 m (253 ft)
The antipode can be calculated by understanding the geographic coordinates and applying simple formulas. We will use the following variables:
Step 1: Obtain the geographic coordinates of Oxford
The DMS coordinates are: 51°45'8'' N 1°15'21.5'' W.
Calculations are easier by using the decimal format, hence:
LatO = 51.75222°
LngO = -1.25596°
Step 2: Calculate the latitude
LatA = - LatO = -51.75222°
Since the latitude is positive (north direction), the antipode must be negative (south direction).
Step 3: Calculate the longitude
LngA = LngO ± 180° = -1.25596 + 180° = 178.74404°
Since the longitude is negative, we sum 180° to ensure the final value lies between (-180, 180). If it were the other way around, we would subtract 180° for the same reason.
Result:
The antipode of Oxford is located on coordinates: (LatA, LngA) = (-51.75222, 178.74404)
In DMS format: 51°45'8'' N 1°15'21.5'' W.