The distance between Samut Prakan, Thailand and Guayaquil, Ecuador is 18,742 kilometers (11,646 miles).
Samut Prakan, Thailand
From Samut Prakan to Guayaquil, the straight-line distance is 18,742 kilometers, heading north. Both cities are at a similar altitude, with Samut Prakan at 2 meters above sea level and Guayaquil at 14 meters.
Mode | Estimated time |
---|---|
Airplane | 1-2 days |
Jet fighter | 1 day |
Speed | Time |
---|---|
300 km/h | |
Local time:
Time Zone: Asia/Bangkok
Coordinates: 13.5976° N 100.5972° E
Elevation: 2 m (7 ft)
Local time:
Time Zone: America/Guayaquil
Coordinates: 2.1962° S 79.8862° W
Elevation: 14 m (46 ft)
Distance between cities | Kilometers |
---|---|
From Samut Prakan to Bangkok | 20 km |
From Samut Prakan to Hat Yai | 729 km |
From Samut Prakan to Pak Kret | 36 km |
From Samut Prakan to Phra Pradaeng | 10 km |
From Samut Prakan to Lampang | 533 km |
Distances between cities | Kilometers |
---|---|
From Guayaquil to Quito | 265 km |
From Guayaquil to Cuenca | 125 km |
From Guayaquil to Ambato | 176 km |
From Guayaquil to Portoviejo | 141 km |
From Guayaquil to Machala | 118 km |
The following list contains cities that are at equal or similar distances as between Samut Prakan and Guayaquil.